In an isosceles triangle ABC, the base is AC = 7 cm and the perimeter is 17 cm. Find the lateral side AB.

Since the triangle ABC is isosceles, then its sides are equal, AB = BC.

The perimeter of the triangle ABC is equal to: Ravs = AB + BC + AC = 2 * AB + AC = 17 cm.

2 * AB = 17 – AC = 17 – 7 = 10 cm.

AB = 10/2 = 5 cm.

Answer: The length of the lateral side AB is 5 cm.



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