In an isosceles triangle ABC, the height BD is 8cm, and the base of the AC is 12cm. Find the length of the side.

BDC triangle (angle D = 90 °).

DC = AC / 2

DC = 6

By the Pythagorean theorem, we find BC.

BC ^ 2 = BD ^ 2 + DC ^ 2

BC ^ 2 = 64 + 36

BC = 10

Answer: the side is 10 cm.



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