In an isosceles triangle ABC with a base AC, the lateral side AB is 10, and the cos of angle A is 4/5. Find the height drawn to the base.
1. Draw the height BH from the top B to the bottom AC;
2. Consider a triangle ABH:
AB = 10;
AH, BH – legs; AB – hypotenuse;
The cosine of the angle is the ratio of the adjacent leg to the hypotenuse;
cos∠A = AH: AB;
3. Find the height BH:
4/5 = AH: 10;
AH = 4/5 * 10 = 8.
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