In an isosceles triangle ABC with base AB, bisectors AA1 and BB1 are drawn. Prove that triangle ABA1

In an isosceles triangle ABC with base AB, bisectors AA1 and BB1 are drawn. Prove that triangle ABA1 is equal to triangle ABB1.

In an isosceles triangle, the angles at the base are equal, the angle CAB = CBA. Since AA1 and BB1 are bisectors of equal angles, the angle CAA1 = BAA1 = CBB1 = ABB1.

In triangles ABA1 and ABB1, side AB is common, angle ABB1 = BAA1, and angle ABA1 = BAB1. Then triangle ABA1 is equal to triangle ABB1 along the side and two adjacent corners, according to the second criterion of equality of triangles, which was required to prove.



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