In an isosceles triangle, the angles at the base are equal to each other. The angles of a triangle add up to 180 °. Find the angle A at the base of the AC:
∠А = (180 ° – ∠В) / 2 = (180 ° – 40º) / 2 = 140º / 2 = 70º.
Since AK is the bisector of angle A, then ∠KAС is equal to half of angle A:
∠KAС = ∠A / 2 = 70º / 2 = 35º.
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