In an isosceles triangle ABC with base AC, the outer angle at apex B is 150 degrees. Find the corner at the base.

The angle ABC is adjacent to the external angle CBD, then the angle ABC = (180 – CBD) = 180 – 150 = 30.

Then the angle BAC = BCA = (180 – 30) / 2 = 150/2 = 75.

Answer: The angle at the base is 75.

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