In an isosceles triangle ABC with base AC, the outer angle at apex B is 150 degrees. Find the corner at the base.
September 20, 2021 | education
| The angle ABC is adjacent to the external angle CBD, then the angle ABC = (180 – CBD) = 180 – 150 = 30.
Then the angle BAC = BCA = (180 – 30) / 2 = 150/2 = 75.
Answer: The angle at the base is 75.
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