isosceles triangle ABC,
ВС – base,
AB and AC – lateral sides,
angle B = 40 degrees,
the KCA angle is adjacent to the ACB angle.
Find the degree measure of the KSA angle -?
Consider an isosceles triangle ABC. Therefore, the sides in it are equal to each other and the angles at the base are also equal, that is, the angle B = angle C = 40 degrees.
Knowing that the sum of the degree measures of the angles is 180 degrees, then
angle ACK = 180 – angle ACB;
angle ACK = 180 – 40;
angle ACK = 140 degrees.
Answer: 140 degrees.
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