In an isosceles triangle ABC with base BC, the measurement is 32 cm. Find the sides of the triangle if AC

In an isosceles triangle ABC with base BC, the measurement is 32 cm. Find the sides of the triangle if AC is 8 cm greater than BC.

Since the triangle ABC is isosceles, then its sides are equal, AB = BC.

Let the length of the base BC = X cm, then, by condition, the sides will be equal:

AB = AC = (X + 8) cm.

The perimeter of the triangle is:

Ravs = (AB + BC + AC) = (X + 8 + X + X + 8) = 32 cm.

3 * X = 32 – 16.

3 * X = 16.

X = 16/3 = 5 (1/3) cm.

BC = 5 (1/3) cm.

AC = BC = 8 + 5 (1/3) = 40/3 = 13 (1/3) cm.

Answer: The sides of the triangle are 5 (1/3) cm, 13 (1/3) cm.