In an isosceles triangle ABC with base BC, the measurement is 32 cm. Find the sides of the triangle if AC is 8 cm greater than BC.
Since the triangle ABC is isosceles, then its sides are equal, AB = BC.
Let the length of the base BC = X cm, then, by condition, the sides will be equal:
AB = AC = (X + 8) cm.
The perimeter of the triangle is:
Ravs = (AB + BC + AC) = (X + 8 + X + X + 8) = 32 cm.
3 * X = 32 – 16.
3 * X = 16.
X = 16/3 = 5 (1/3) cm.
BC = 5 (1/3) cm.
AC = BC = 8 + 5 (1/3) = 40/3 = 13 (1/3) cm.
Answer: The sides of the triangle are 5 (1/3) cm, 13 (1/3) cm.
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