In an isosceles triangle ABC with the base of the AC, the bisector AD is drawn, find the angle ADC

In an isosceles triangle ABC with the base of the AC, the bisector AD is drawn, find the angle ADC if the angle C is 50 degrees.

Since ABC is an isosceles triangle, angle A is equal to angle C (in an isosceles triangle, the angles at the base are equal), angle A = 50 °.

Since AD is a bisector, the DAC angle is 50 °: 2 = 25 °.

The angles in a triangle add up to 180 °. In triangle ADC: angle ADC = 180 ° – (50 ° + 25 °) = 105 °.



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