In humans, myopia dominates over normal vision. A woman with normal vision marries a short-sighted man whose mother had normal vision. What is the probability of being born in this family with myopia (express as a percentage)?
A – myopia, and – normal vision.
A woman has normal vision, which means she is homozygous for a recessive trait – aa.
The mother of the short-sighted man also had normal vision and was recessive homozygous, hence the man is heterozygous – Aa.
Let’s draw up a scheme for solving the problem:
p ♀aa x ♂Aa
g a A a
F1 Aa – myopia
aa – normal vision
The probability of having a short-sighted child is 50%.
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