In one test tube there is a solution of sodium chloride, in the other – potassium sulfate. how to distinguish

In one test tube there is a solution of sodium chloride, in the other – potassium sulfate. how to distinguish the contents of tubes? make up the equations of the reactions that need to be carried out for this.

In the condition of this problem, they were a little too clever. The fact is that there are two ways to identify which substance of the two offered in test tubes. Well, in order to simply distinguish in which test tube. what substance is enough and one method and one reagent.

1 way. AgNO3 is added.

And here is the reaction in which the precipitate falls.

NaCl + AgNO3 = NaNO + AgCl (sediment)

In the case of potassium sulfate, no precipitate will form).

2. method.

Add Ba (NO3) 2.

K2SO + Ba (NO3) 2 = 2KNO3 + BaSO4 (curdled sediment).

In another test tube, the precipitate will not fall out.




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