In parallelogram ABCD AB = 3, BM is the bisector of angle B, where point M is the midpoint of side AD. find the perimeter of the parallelogram.
1. The bisector BM of the parallelogram ABCD cuts off the triangle ABM, which is isosceles. Therefore, AB = BM = 3 units.
2. AD = AM + DM = 3 + 3 = 6 units of measurement.
3. The total length of all sides of the parallelogram (perimeter) = 2AB + 2 AD = 2 x 3 + 2 x 6 = 6 +12 = 18 units.
Answer: the total length of all sides of the parallelogram (perimeter) is 18 units.
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