In parallelogram ABCD AB = AD. Angle BDC = 62 degrees Find the angle BAC.

Since in a parallelogram two adjacent sides are equal, AB = AD, such a parallelogram is a rhombus.

By the property of a rhombus, its diagonal BD is the bisector of the angle ADC, then the angle ADC = 2 * BDC = 2 * 62 = 124.

The sum of the adjacent angles of the rhombus is 180, then the angle BAD = (180 – 124) = 56.

The diagonal AC is the bisector of the angle BAD, then the angle BAC = BAD / 2 = 56/2 = 28.

Answer: The value of the angle BAC is 28.

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