The first way. The area of a parallelogram is equal to the product of the lengths of its sides by the sine of the angle between them.
Savsd = CD * AD * Sin30 = 8 * 14 * (1/2) = 56 cm2.
Let us draw the height of CH, then in a right-angled triangle CDH the leg of CH lies opposite angle 30 and is equal to half the length of the hypotenuse CD. CH = CD / 2 = 8/2 = 4 cm.
Then Savsd = AD * CH = 14 * 4 = 56 cm2.
Answer: The area of the parallelogram is 56 cm2.
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