In rabbits, hair of normal length gene (L) is dominant, which is (l) recessive. The short-haired rabbit
In rabbits, hair of normal length gene (L) is dominant, which is (l) recessive. The short-haired rabbit gave birth to 5 rabbits, 3 short-haired and 2 with normal hair. Make a crossing scheme. Determine the genotype of the father, the genotypes of the mother of the offspring.
According to the designations introduced in the condition of the problem, we will write the short-haired rabbit as ll, because homozygosity is an indispensable condition for the development of her short hair. The rabbit’s body produces eggs l.
Since in the offspring of the rabbit there are both short-haired rabbits – ll, and rabbits with hair of normal length – Ll (because only the gene for short hair can be inherited from the mother of the rabbits), it should be concluded that the rabbit is heterozygous – Ll. Such a rabbit has a coat of normal length and produces spermatozoa L and l.
Therefore, the offspring of such rabbits looks like this:
50% Ll – rabbits with normal length hair;
50% ll are short-haired rabbits.
Answer: rabbit – ll, rabbit – Ll, rabbits with normal coat length – Ll, short-haired rabbits – ll.