# In rhombus ABCD, where O is the intersection of the diagonals BD and AC, the angle BAD is 110 °

March 24, 2021 | education

| **In rhombus ABCD, where O is the intersection of the diagonals BD and AC, the angle BAD is 110 °. find the corners of triangle AOB.**

In a rhombus, the sum of opposite angles is 180, then the angle ABC = 180 – BAD = 180 – 110 = 70.

The diagonals of the rhombus divide the angles at the vertices of the rhombus in half, and a right angle is formed at the point of intersection of the diagonals. Then triangle AOB is rectangular, angle ABO = BCD / 2 = 70/2 = 350, angle BAO = BAD / 2 = 110/2 = 55.

Answer: The angles of the BOC triangle are 35, 55, 90.

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