In right-angled triangles ABC with hypotenuse AC, the height BK is drawn. Angle C is 60 degrees. What is the side of AK if CK = 5 cm?
In a right-angled triangle, BKC tg60 = BK / KC.
BK = KC * tg60 = 5 * √3 cm.
The height BK is drawn from the top of the right angle to the hypotenuse AC, then:
BK ^ 2 = AK * CK.
AK = BK ^ 2 / CK = (5 * √3) 2/5 = 15 cm.
Answer: The length of the AK segment is 15 cm.
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