# In the coil of an electric heater made of nickel wire with a cross-sectional area of 0.1 mm² at a voltage of 220V

In the coil of an electric heater made of nickel wire with a cross-sectional area of 0.1 mm² at a voltage of 220V, the current strength is 4A. How long is the wire that makes up the spiral?

To find out the length of the wire that makes up the spiral under consideration, we use the equality: ρn * l / S = R (spiral resistance) = U / I, from where we can express: l = S * U / (ρn * I).

Const: ρн – beats. electrical resistance of nickel (prin. ρн = 0.4 Ohm * mm2 / m);

Data: S – wire cross-section (S = 0.1 mm2); U – voltage (U = 220 V); I is the current in the coil (I = 4 A).

Let’s make a calculation: l = S * U / (ρн * I) = 0.1 * 220 / (0.4 * 4) = 13.75 m.

Answer: The wire that makes up the spiral in question should have a length of 13.75 m.

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