In the cylinder under the piston, a gas volume of 15 liters is cooled isobarically from a temperature of 423K

In the cylinder under the piston, a gas volume of 15 liters is cooled isobarically from a temperature of 423K to a temperature of 273K, which will be the volume of gas at a temperature of 273K.

Given:
V1 = 15 l
T1 = 423 K
T2 = 273 K
p1 = p2 – with isobaric cooling, the gas pressure does not change
V2 -?
Solution:
p1 = p2 = const,
V1 / T1 = V2 / T2 – equality from the Cliperon-Mendeleev formula
V1 / V2 = T1 / T2
V2 = V1 * T2 / T1
V2 = 15 * 273/423 = 9.7 l