In the rectangle ABCD, the straight line DH is drawn so that DC = HC. Find the angle ADH.

In a right-angled triangle СDН, by condition, DC = НС, then the triangle is isosceles and right-angled, which means the angle СDН = СНD.

The sum of the inner angles of the triangle is 180, then the angle СDН = СНD = (180 – 90) / 2 = 45.

Angle ADC = 90, then the angle ADH = ADC – CDH = 90 – 45 = 45.

Answer: The value of the ADH angle is 45.

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