In the sailfish butterfly, the gene for body coloration and the gene for the presence of a protuberance on the wing are dominant and are located at a distance of 6 morganids. What offspring can be expected from a cross between a heterozygous female and an unpainted male without a wing protrusion?
Let’s designate the gene that determines the development of body color in a sailfish butterfly as C, then the unpainted body of the butterfly will be determined by the c gene.
Let’s designate the gene that causes the presence of a protrusion on the wing of a sailboat butterfly as D, then the gene that causes the absence of such a protrusion will be designated as d.
The female, according to the condition, is heterozygous for both traits – CcDd. EE body is painted and there is a ledge on the wing. 94% of her gametes are CD and CD eggs.
6% of gametes are formed by crossover types of oocytes – cD, Cd.
An unpainted male with no wing protrusion will be designated ccdd. The sperm produced by him will be of the same type – cd.
The offspring of this pair of sailing butterflies will be represented by the following options:
butterflies with a painted body and a projection on the wing (СсDd) – 47%;
butterflies with an unpainted body and without a protrusion on the wing (ccdd) - 47%
butterflies with an unpainted body and a projection on the wing (ccDd) – 3%;
butterflies with a painted body without a projection on the wing (Ccdd) – 3%.