In the trapezium ABCD, a straight line parallel to the side of the CD and intersecting the side at point E is drawn from the apex of the angle b, so that the angle ABE = 75, angle A = 40. What is the angle of CBE.
Let’s extend the segment AB to AB1.
Angle BAD = B1BC as the corresponding angles at the intersection of parallel straight lines AD and BC secant AB1.
The angle ABB1 is expanded and is equal to 180, then the angle BCE = ABB1 – B1BC – ABE = 180 – 40 – 75 = 65.
Answer: Angle BCE = 65.
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