In the triangle AB, H – the middle AB CH perpendicular to AB BC = 7.2 Find-AC.

In triangles ACH and BCH, the leg CH is common, and AH = BH by condition, angles AHC = BHC = 90, then triangle AHC = BHC along two legs. Since the triangles are equal, AC = BC = 7.2 cm.
Answer: The length of the BC side is 7.2 cm.

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