In triangle ABC, AB is less than AC and less than BC. Find the angles of the triangle BAC, ABC, BCA, if it is known that one of the angles is straight and the other is 40
AB <AC <BC,
one of the catch is straight,
the second is 40.
Find the degree measures of the angles BAC, ABC, BCA -?
1) Consider a right-angled triangle ABC. We know that the sum of the degree measures of any triangle is 180 degrees. Therefore, the third angle is 180 – 90 – 40 = 50.
2) Opposite the larger side is a larger angle, opposite the smaller side is a smaller angle.
Since AB <AC <BC, the largest side is BC, then the angle BAC = 90, angle AB = 50, angle BCA = 40.
Answer: angle BAC = 90, angle AB = 50, angle BCA = 40.
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