In triangle ABC, AD is a bisector, angle C is 62, angle CAD is 32. Find corner B.

To begin with, let’s draw a triangle ABC, in which we draw a bisector AD.
Since the bisector AD divides the angle in half, the angle CAD = BAD = 32 °.
Then the whole angle A = 32 + 32 = 64о.
Since, according to the condition of the problem, we are also given an angle C, which is 62 °, and the sum of the angles is 180 °, then the angle B = 180 – 62 – 64 = 54 °.
Answer: 54 p.

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