In triangle ABC, angle a is 17, angle B = 23 degrees. CH-height Find the difference between

In triangle ABC, angle a is 17, angle B = 23 degrees. CH-height Find the difference between the angles ACH and BCH.

Find angle C:

angle С = 180 ° – (23 ° + 17 °) = 140 °. since CH is the bisector => angle C and I of the triangle ACH, and in the triangle BCH = 70 ° degrees.

Next, we find the angle H:

Consider a triangle ACH, it is rectangular, and the angle A = 17 °, so the angle H = 180 ° – (70 ° + 17 °) = 93 °.

Consider a triangle BCH, angle H = 180 ° – (70 ° + 23 °) = 87 °.

Let’s find the difference between the angles ACH and BCH:

angle АСН – angle ВСН = 93 ° – 87 ° = 6 °.

Answer: the difference between the angles ACH and BCH is 6 °.