In triangle ABC, angle A is 3 times greater than angle B, and angle C is 2 times greater than angle A.

In triangle ABC, angle A is 3 times greater than angle B, and angle C is 2 times greater than angle A. Calculate the angles of triangle ABC.

We take the value of the angle A for x, then:

x: 3 = x / 3 – angle B;

x * 2 – value C.

Since the sum of the angles of the triangle is 180 °, we get the equation:

x + x / 3 + 2x = 180.

Multiply the equation by 3:

3x + x + 6x = 540;

10x = 540;

x = 54 °.

Then B is equal to:

54: 3 = 18 °.

And angle C:

54 * 2 = 108 °.

Answer: The angles of the triangle are 54 °, 18 ° and 108 °, respectively.