In triangle ABC, angle A is 38 °, AC = BC. Find corner C.

1. It is known that:

a) in an isosceles triangle, the angles at the base are equal;

b) The sum of the angles of the triangle is 180 *.

2. According to the condition of the problem AC = BC, angle A = 38 *.

We have an angle at the base of 38 * in an isosceles triangle, which means that the second angle at the base of B is 38 *.

3. Let’s calculate the angle C.

Angle C + angle B + angle A = 180 *; so

angle C = 180 * – 38 * – 38 * = 104 *.

Answer: In triangle ABC, angle C is 104 *.

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