In triangle ABC, angle C is 90, CH is height, and angle A is 53. find the corner BCH.

First, we need to find angle B.

53 ° + 90 ° = 143 °,

180 ° – 143 ° = 37 ° (angle B).

And so we learned that in the triangle BCH the angle B = 37 °, the angle H = 90 ° and it remains to find the angle C.

90 ° + 37 ° = 127 °,

180 ° – 127 ° = 53 ° (angle C).

Answer: in triangle BCH, the angle BCH = 53 °.



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