In triangle ABC, angle C is 90 degrees, AB = 95, AC = 76. Find tgA.

Determine the cosine of the angle BAC.

CosBAC = AC / AB = 76/95 = 4/5.

Through the cosine of the angle BAC, we determine the tangent of the angle BAC.

tg2BAC = 1 / Cos2BAC – 1 = 1 / (16/25) – 1 = (25/16) – 1 = 9/16.

tgBAC = 3/4.

Answer: The tangent of the angle BAC is 3/4.




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