In triangle ABC, angle C is 90 degrees, AC = 8, tangent of angle A is 0.75. Find BC.

Consider a right-angled triangle ABC.

Since the tangent of an acute angle of a right-angled triangle is equal to the ratio of the opposite leg to the adjacent leg, then

tg A = BC / AC,

0.75 = BC / 8;

BC = 8 * 0.75;

BC = 6.

Answer. BC is 6

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