In triangle ABC, angle C is 90 degrees. BC = 12. cosA = 3/5. Find AB.

In a right-angled triangle ABC, we define the sine of the angle BAC.

Cos2BAC + Sin2BAC = 1.

Sin2BAC = 1 – Cos2BAC = 1 – (3/5) 2 = 1 – 9/25 = 16/25.

SinBAC = 4/5.

Through the sine of the angle BAC and the length of the opposite leg, we determine the length of the hypotenuse AB.

SinBAC = BC / AB.

AB = BC / SinBAC = 12 / (4/5) = 12 * 5/4 = 15 cm.

Answer: The length of the hypotenuse AB is 15 cm.



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