In triangle ABC, angle C is 90 degrees, BC = 8, cosA = 0.5. Find the height CH.

Let the angle A = X0, then the angle HCA = (90 – X) 0, and the angle BCH = (90 – (90 – X)) = X0.

Then the angle BAC = BCH, which means CosBCH = 0.5.

In a right-angled triangle BCH Cosvsn = ВН / ВС.

ВН = ВС * Сosвсн = 8 * 0.5 = 4 cm.

Answer: The length of the CH height is 4 cm.




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