In triangle ABC, angle C is 90 degrees, CH is height, AC = 4, sinA = √7 / 4. Find AH.
July 29, 2021 | education|
Determine the cosine of the angle BAC.
Sin2BAC + Cos2BAC = 1.
Cos2BAC = 1 – Sin2BAC = 1 – 7/16 = (16 – 7) / 16 = 9/16.
CosBAC = 3/4.
Then CosBAC = AH / AC.
AH = AC * CosBAC = 4 * √7 / 4 = √7 cm.
Answer: The length of the segment AH is equal to √7 cm.
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