In triangle ABC, angle C is 90 degrees, tgA = 15 | 8, BC = 15. Find AB

Through the tangent of the angle BAC, we determine the sine of this angle.

Sin2BAC = 1 / (1 + (1 / tg2BAC)) = 1 / (1 + 64/225) = 225/289.

SinBAC = 15/17.

Let us determine the length of the hypotenuse AB.

SinBAC = BC / AB.

AB = BC / CosBAC = 15 / (15/17) = 17 cm.

Answer: The length of the hypotenuse AB is 17 cm.



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