In triangle ABC CH-height AD -bisector o – point of intersection of lines CH and AD angle BAD = 26 find angle AOC

Since AD is the bisector of the BAC angle, the BAD angle is equal to the DAC angle, then the BAC angle = 2 * BAD = 2 * 26 = 52.

The ACH triangle is rectangular, since the CH is the height in the side of AB, then the angle ACH = 180 – AHC – CAH = 180 – 90 – 52 = 38.

In the AOC triangle, the angle AOC = 180 – CAO – ACH = 180 – 38 – 26 = 116.

Answer: The AOC angle is 116.