In triangle ABC it is known that AB = 6cm, angle BAC = 45 degrees, angle BCA = 30 degrees. Find BC.

For the solution we use the theorem of sines for triangles.

AB / SinACB = CB / BAC.

6 / Sin30 = BC / Sin45.

6 / (1/2) = BC / (√2 / 2).

BC = 12 * (√2 / 2) = 6 * √2 cm.



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