In triangle ABC, the outside angle at vertex B is 148 degrees and the BAC angle is 58 degrees. Find the angle ACB.

The angle ABC is adjacent to the angle CBD, the sum of which is 180, then the angle ABC = (180 – 148) = 32.

The sum of the inner angles of the triangle is 180, then the angle ACB = (180 – 58 – 32) = 90.

Answer: The angle ACB is 90.

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