In triangle ABC, vertex B is symmetric to point K relative to the bisector of the outer corner at vertex A. find the segment CK, If AB = 3 cm, AC = 5 cm.
In order to find CK, we need to add AC and KA. By the condition of the problem, we know AC = 5. we need to find the CA. From the condition, we can conclude that point K is symmetric to point B, from here we can conclude that KA = AB = 3.
СK = 5 + 3;
СK = 8.
Answer: the segment is 8.
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