In two vessels with a green solution of copper sulphate they were placed: in the first, a copper plate, in the second, a zinc plate. In which vessel does the color of the solution gradually drop? Why? Write the electronic and molecular equations of the corresponding reaction.
The solution in which the zinc plate is placed will gradually discolor, since the copper reduction reaction and the formation of colorless zinc sulfate will take place in it.
Zn + CuSO4 = Cu + ZnSO4
Zn0 – 2e = Zn2+ | * 1 – reducing agent, is oxidized.
Cu2+ + 2e = Cu0 | * 1 – oxidizing agent, reduced.
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