Inscription a rectangle with sides 3cm and 4cm. divide it by a segment into two triangles. find the perimeter of one of the triangles
4 cm and 3 cm are the sides of the rectangle.
We find the length of the diagonal using the Pythagorean theorem.
c ^ 2 = a ^ 2 + b ^ 2.
3 ^ 2 + 4 ^ 2 = 9 + 16 = 25.
25 = 52.
5 cm – the diagonal of the rectangle and the side of the triangle.
P tr = a + b + c.
P tr = 3 + 4 + 5 = 12.
12 cm is the perimeter of one of the triangles.
Solution: 12 cm perimeter of one of the triangle.
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