Iron and aluminum balls of the same mass fell to the floor from a height of 2m

Iron and aluminum balls of the same mass fell to the floor from a height of 2m, which ball will heat up when hitting to a higher temperature.

Given: m = m1 (mass of an iron ball) = m2 (mass of an aluminum ball); h (drop height of the balls) = 2 m.

Reference values: C1 (specific heat of iron) = 460 J / (kg * K); C2 (specific heat of aluminum) = 920 J / (kg * K).

Since the balls have the same mass and fell from the same height, the equality will be true: Q1 = En = Q2.

C1 * m1 * Δt1 = C2 * m2 * Δt2.

C1 * Δt1 = C2 * Δt2.

460 * Δt1 = 920 * Δt2 and Δt1 / Δt2 = 920/460 = 2 times.

Answer: The iron ball will heat up to a higher temperature.

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