Is it possible to mark point C on the segment AB so that the length of the segment AC is 8/15 of the length of the segment AB, and the length of the segment BC is 11/20 of the length of the segment AB.
To complete this task, it is necessary to put point C in such a way that it satisfies the condition of the problem. Consider the condition of the problem and analyze it;
According to the condition of the assignment, we are given a segment AB, on which there is a point C, which divides this segment into two segments AC and CB. Since both segments AC and CB are equal in length to AB, then we can write the equation;
8/15 + 11/20 = 1;
Let us bring the fractions to a common denominator 60 and get;
8/15 = 24/60;
11/20 = 33/60;
24/60 + 33/60 = 1;
57/60 = 1;
Since the left and right parts are not equal, it means that it is impossible to divide the segment AB so that it satisfies the condition.
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