Magnesium carbonate with the amount of substance 0.25 mol was completely decomposed by heating without air access. Calculate the mass of the solids and the volume of gas that have formed.
The decomposition reaction of magnesium carbonate when heated is described by the following chemical equation:
MgCO3 = MgO + CO2 ↑;
By the condition of the problem:
N MgCO3 = 0.25 mol;
The same molar amount of magnesium oxide can theoretically be obtained.
Let’s calculate its weight.
M MgO = 24 + 16 = 40 grams / mol;
m MgO = 0.25 x 40 = 10 grams;
The same molar amount of carbon dioxide could theoretically be synthesized.
To calculate its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).
V CO2 = 0.25 x 22.4 = 5.6 liters;
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