# Moving uniformly accelerated, the body within the third second from the beginning

Moving uniformly accelerated, the body within the third second from the beginning of the movement passed 20m. What is the acceleration with which the body was moving and the speed of the body at the end of the 6th second?

Given:

S = 20 meters – the distance covered by the body in the third second.

It is required to find the body’s acceleration a and the velocity at the end of the 6th second V.

In three seconds, the body will cover the distance:

S1 = a * 3 * 3/2 = 4.5 * a.

In two seconds, the body will cover the distance:

S2 = a * 2 * 2/2 = 2 * a.

In the third second of movement, the body will cover a distance equal to S1 – S2 = S:

4.5 * a – 2 * a = 20

2.5 * a = 20

a = 20 / 2.5 = 8 m / s ^ 2.

The speed of the body at the end of the 6th second is found from the formula:

v = a * t = 8 * 6 = 48 m / s.

Answer: the acceleration of the body is 8 m / s ^ 2, the speed of the body at the end of the 6th second is 48 m / s.

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