Moving with an initial speed of 36 km / h, the car drove in 10 from 105 m.

Moving with an initial speed of 36 km / h, the car drove in 10 from 105 m. With what acceleration did the car move, what is its speed at the end of the path

Let’s convert the speed from (km / h) to (m / s):

36 (km / h) = 36 * 1000/3600 (s) = 10 (m / s).

To determine acceleration (a), we use the equation for rectilinear uniformly accelerated motion:

s = v0 * t + a * t ^ 2/2,

where s is the path traveled by the car, v0 is its initial speed, t is the time of movement.

Let us express from this equation a:

s – v0 * t = a * t ^ 2/2,

a = 2 * (s – v0 * t) / t2.

Let’s substitute numerical values ​​into the last formula:

a = 2 * (10 ^ 5 – 10 * 10) / 10 ^ 2 = 10/100 = 0.1 (m / s2).

To determine the final speed of the car, we use the formula:

v = v0 + a * t,

we substitute the numerical values ​​of physical quantities:

v = v0 + a * t = 10 + 0.1 * 10 = 10 + 1 = 11 (m / s).

Answer: a = 0.1 (m / s2), v = 11 (m / s).