# Moving with an initial speed of 36 km / h, the car drove in 10 from 105 m.

**Moving with an initial speed of 36 km / h, the car drove in 10 from 105 m. With what acceleration did the car move, what is its speed at the end of the path**

Let’s convert the speed from (km / h) to (m / s):

36 (km / h) = 36 * 1000/3600 (s) = 10 (m / s).

To determine acceleration (a), we use the equation for rectilinear uniformly accelerated motion:

s = v0 * t + a * t ^ 2/2,

where s is the path traveled by the car, v0 is its initial speed, t is the time of movement.

Let us express from this equation a:

s – v0 * t = a * t ^ 2/2,

a = 2 * (s – v0 * t) / t2.

Let’s substitute numerical values into the last formula:

a = 2 * (10 ^ 5 – 10 * 10) / 10 ^ 2 = 10/100 = 0.1 (m / s2).

To determine the final speed of the car, we use the formula:

v = v0 + a * t,

we substitute the numerical values of physical quantities:

v = v0 + a * t = 10 + 0.1 * 10 = 10 + 1 = 11 (m / s).

Answer: a = 0.1 (m / s2), v = 11 (m / s).