Nitrobenzene with a mass of 12.3 g was reduced to aniline with a yield of the reaction product 80. Calculate the mass of the obtained aniline.
The reaction equation for the reduction of nitrobenzene to aniline:
C6H5NO2 + 6 [H] = C6H5NH2 + 2H2O
The amount of nitrobenzene substance:
v (C6H5NO2) = m (C6H5NO2) / M (C6H5NO2) = 12.3 / 123 = 0.1 (mol).
According to the reaction equation, from 1 mol of C6H5NO2, 1 mol of C6H5NH2 is formed, therefore, taking into account the reaction yield:
v (C6H5NH2) = v (C6H5NO2) * 0.8 = 0.1 * 0.8 = 0.08 (mol).
Thus, the mass of the obtained aniline:
m (C6H5NH2) = v (C6H5NH2) * M (C6H5NH2) = 0.08 * 93 = 7.44 (g).
Answer: 7.44 g.
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