Nitrobenzene with a mass of 12.3 g was reduced to aniline with a yield of the reaction product 80.

Nitrobenzene with a mass of 12.3 g was reduced to aniline with a yield of the reaction product 80. Calculate the mass of the obtained aniline.

The reaction equation for the reduction of nitrobenzene to aniline:

C6H5NO2 + 6 [H] = C6H5NH2 + 2H2O

The amount of nitrobenzene substance:

v (C6H5NO2) = m (C6H5NO2) / M (C6H5NO2) = 12.3 / 123 = 0.1 (mol).

According to the reaction equation, from 1 mol of C6H5NO2, 1 mol of C6H5NH2 is formed, therefore, taking into account the reaction yield:

v (C6H5NH2) = v (C6H5NO2) * 0.8 = 0.1 * 0.8 = 0.08 (mol).

Thus, the mass of the obtained aniline:

m (C6H5NH2) = v (C6H5NH2) * M (C6H5NH2) = 0.08 * 93 = 7.44 (g).

Answer: 7.44 g.