# On a conductor 30 cm long, located perpendicular to the lines of magnetic induction, a force of 0.6 N acts

On a conductor 30 cm long, located perpendicular to the lines of magnetic induction, a force of 0.6 N acts. Find the current in the conductor if the induction of the magnetic field is 0.4 T.

Given: l (conductor length) = 30 cm (0.3 m); the taken conductor is located perpendicular to the lines of magnetic induction (α = 90º); Fa (acting force of Ampere) = 0.6 N; B (magnetic induction value) = 0.4 T.

You can express and calculate the current in a conductor using Ampere’s law: Fa = I * B * l * sinα and I = Fa / (B * l * sinα).

Calculation: I = 0.6 / (0.4 * 0.3 * sin 90º) = 5 A.

Answer: The current in the taken conductor is 5 A.

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