# On a conductor 50 cm long with a current of 2A, a uniform magnetic field with a magnetic induction of 0.1

**On a conductor 50 cm long with a current of 2A, a uniform magnetic field with a magnetic induction of 0.1 T acts with a force of 0.05 N. Calculate the angle between the direction of the current and the vector of magnetic induction.**

Given: l (length of a conductor placed in a uniform magnetic field) = 50 cm (0.5 m); I (current) = 2 A; B (value of magnetic induction) = 0.1 T; Fа (Ampere force acting on the conductor) = 0.05 N.

You can calculate the angle between the direction of the current and the vector of magnetic induction using Ampere’s law: Fa = I * B * l * sinα and sinα = Fa / (I * B * l).

Calculation: sinα = 0.05 / (2 * 0.1 * 0.5) = 0.5 (hence α = 30º).

Answer: The angle between the direction of the current and the vector of magnetic induction is 30º.