One corner of a triangle is 2 times the other and 25 degrees less than the third. Find all the corners of the triangle.

1. Let’s denote the angles of the triangle by A, B and C.
Then the first equation: A + B + C = 180 o.

2. By the condition of the problem, A = 2 * B (second equation) and A = C – 25 o (third equation).

3. From the third equation, taking into account the second: C = A + 25 = 2 * B + 25.

4. Substitute the expressions for A and C in the first equation. We get:
2 * B + B + 2 * B + 25 = 5 * B + 25 = 180. Hence B = 155/5 = 31 p.

5. Therefore, A = 2 * B = 2 * 31 = 62 o, and C = A + 25 = 62 + 25 = 87 o.

Answer: the angles of the triangle have the following meanings: A = 31 o, B = 62 o, C = 87 o.